The height of a ball t seconds after it is thrown upward from a height of 6
Question:
The height of a ball t seconds after it is thrown upward from a height of 6 feet and with an initial velocity of 48 feet per second is ƒ(t) = − 16t² + 48t + 6.
(a) Verify that ƒ(1) = ƒ(2).
(b)
According to Rolle's Theorem, what must the velocity be
at some time in the interval (1, 2)? Find that time.
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