Solve the initial-value problem. dv/dt 2tv = 3t 2 e t 3 , v(0) = 5
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Solve the initial-value problem.
dv/dt – 2tv = 3t2et3, v(0) = 5
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To solve the initialvalue problem dvdt 2tv 3t2e3t v0 5 you can use the method of integrating factors First lets rewrite the differential equation in s...View the full answer
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