Let f () = log b (3 2 2). For what value of b is f'

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Let f (ϰ) = logb(3ϰ2 – 2). For what value of b is f' (1) = 3?

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Calculus Early Transcendentals

ISBN: 9781337613927

9th Edition

Authors: James Stewart, Daniel K. Clegg, Saleem Watson, Lothar Redlin

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