Question: Suppose that object A is located at s = 0 at time t = 0 and starts moving along the s-axis with a velocity given

Suppose that object A is located at s = 0 at time t = 0 and starts moving along the s-axis with a velocity given by v(t) = 2at, where a > 0. Object B is located at s = c > 0 at t = 0 and starts moving along the s-axis with a constant velocity given by V(t) = b > 0. Show that A always overtakes B at time

b + Vb² + 4ac t = 2a

b + Vb + 4ac t = 2a

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