A ball is thrown vertically upward from the ground at a velocity of 64 ft per second.
Question:
A ball is thrown vertically upward from the ground at a velocity of 64 ft per second. Its distance from the ground at t seconds is given by s(t) = -16t2 + 64t.
(a) How fast is the ball moving 2 seconds after being thrown? 3 seconds after being thrown?
(b) How long after the ball is thrown does it reach its maximum height?
(c) How high will it go?
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st 16t 2 64t a vt st 162t 64 32t 64 v2 322 64 64 64 0 v3 323 64 96 64 32 The balls velocity ...View the full answer
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