Question: If a rock is dropped from a 144-ft building, its position (in feet above the ground) is given by s(t) = -16t 2 + 144,

If a rock is dropped from a 144-ft building, its position (in feet above the ground) is given by s(t) = -16t² + 144, where t is the time in seconds since it was dropped.
(a) What is its velocity 1 second after being dropped? 2 seconds after being dropped?
(b) When will it hit the ground?
(c) What is its velocity upon impact?

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