Question: If an object is dropped or thrown vertically, its height (in feet) after t seconds is H(t) = 16t 2 + V 0 t +

If an object is dropped or thrown vertically, its height (in feet) after t seconds is H(t) = −16t² + V₀t + H₀, where V₀ is the initial speed of the object and H₀ is its initial height.

a. Derive an expression for the acceleration of the object.

b. How does the acceleration vary with time?

c. What is the significance of the fact that the answer to part (a) is negative?

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