The asymmetric bar shown has a weight of 7.6 N and a centre of gravity that is 0.040 m from the wider end, on which there is a load of 3.3 N. It is pivoted a distance of 0.060 m from its centre of gravity. Calculate the force P that is needed at the far end of the bar in order to maintain equilibrium.

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0.040 m 0.060 m 0.080 m load pivot V W=7.6 N load = 3.3 N Figure 4.33