The reaction taking place in an electrochemical cell under standard conditions is Fe 2+ (aq) + Ag

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The reaction taking place in an electrochemical cell under standard conditions is Fe2+(aq) + Ag+(aq) Fe3+(aq) + Ag(s)

a. Write two half-equations for this reaction. For each, state whether oxidation or reduction is occurring.

b. The standard electrode potential for the half-cell containing Fe2+(aq) and Fe3+(aq) is +0.77V.

i. Use the relationship E = Eθ + 0.059/Z  log10 [oxidized form]/[reduced form] to calculate the electrode potential at 298 K if the concentration of Fe2+(aq) is 0.02 mol dm3 and the concentration of Fe3+(aq) is 0.1 mol dm–3.

ii. Use the relationship above to explain why the standard electrode potential for the half cell containing Fe2+(aq) and Fe3+(aq) is always +0.77 V if there are equimolar concentrations of Fe2+(aq) and Fe3+(aq).

c. The standard electrode potential for the half-cell containing Ag+(aq) and Ag(s) is +0.80 V. Calculate the electrode potential at 298K if the concentration of Ag+(aq) is 0.05 mol dm–3.

d. Use your results to parts b i and c to predict whether the reaction Fe2+(aq) + Ag+(aq) → Fe3+(aq) + Ag(s) is likely to occur at the concentrations Fe2+(aq) 0.05 mol dm–3, Fe3+(aq) 0.1 mol dm–3 and Ag+(aq) 0.05 mol dm–3. Explain your answer.

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