Question: A 2 J table has ordinal response. Let F j|i = 1|i + ..... + j|i . When F j|2 F
A 2 × J table has ordinal response. Let Fj|i= Ï€1|i+ ..... + Ï€j|i. When Fj|2‰¤ Fj|1for j = 1,......, J, the conditional distribution in row 2 is stochastically higher than the one in row 1. Consider the cumulative odds ratios

Show that log θj > 0 for all j is equivalent to row 2 being stochastically higher than row 1. Explain why row 2 is then more likely than row 1 to have observations at the high end of the ordinal scale.
F1/(1 - F) Fj2/(1 - Fj2)" j = 1..., J - 1.
Step by Step Solution
3.48 Rating (165 Votes )
There are 3 Steps involved in it
log j 0 ... View full answer
Get step-by-step solutions from verified subject matter experts
