An alternative ordinal model for square tables, called the conditional symmetry model, has form log(ij/Mji) = , for all i < j. Show that symmetry is the special case = 0. Comparing the fit of this model to the symmetry model provides an alternative ordinal test of marginal homogeneity. Do this for Table 9.6, and interpret. (The ordinal quasi-symmetry model has the advantage of extending naturally to multiway tables, as discussed in the previous problem.)