Question: How is the focus different for the model in Problem 12.3 than for the loglinear model (AC, AM, CM) used in Section 8.2.4? If ÏÌ
Data from Problem 12.3:
For table 8.3, let yit = 1 when subject i used substance t. Table 12.11 shows output for the logistic-normal model
logit[P(Yit = 1|ui)] = ui + βt.
Interpret. Illustrate by comparing use of cigarettes and marijuana.
Table 8.3:

Table 12.11:

Alcohol, Cigarette, and Marijuana Use for High School Seniors Marijuana Use Alcohol Cigarette Use Use Yes No 911 Yes Yes 538 No 44 456 No Yes 3 43 No 279 2. Output Description Subjects Max Obs Per Subject Value Std Error 0.1824 Parameter betal beta2 beta3 Estimate 4.2227 1.6209 -0.7751 3.5496 2276 t Value 23.15 Parameters Quadrature Points Log Likelihood 0.1207 13.43 200 0.1061 0.1627 -7.31 21.82 -3311 sigma
Step by Step Solution
3.45 Rating (165 Votes )
There are 3 Steps involved in it
With the loglinear model one is focusing on the strength of association between use of one subs... View full answer
Get step-by-step solutions from verified subject matter experts
