Derive Eqs. 6.6-2 and 6.6-3, and show that Z c | van der Waals = 3/8. Eqs.

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Derive Eqs. 6.6-2 and 6.6-3, and show that Zc|van der Waals = 3/8.

 Eqs. 6.6-2

(OP) 7 / Va T evaluated at Te, Pe.Ve (OVP) evaluas = 0 = evaluated at Te, Pe.Ve = 0 = = 2a RTC (Ve-b) V3 +

Eqs. 6.6-3,

and a = Pe Using these results in Eq. 6.6-2a yields Zc = 9V RTC 8 b a 276 By direct substitution we find that

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