Lead ions can be precipitated from solution with KCl according to the reaction: When 28.5 g KCl
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Lead ions can be precipitated from solution with KCl according to the reaction:
When 28.5 g KCl is added to a solution containing 25.7 g Pb2 + , a PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.4 g. Determine the limiting reactant, theoretical yield of PbCl2, and percent yield for the reaction.
Transcribed Image Text:
Pb²+ (aq) + 2 KCl(aq) PbCl₂(s) + 2 K+ (aq)
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