(a) Repeat the problem two problems prior, but for the second leg you walk 20.0 m in a direction 40.0°).

(b) Repeat the problem two problems prior, but now you first walk 20.0 m in a direction 40.0° east of south (which is equivalent to subtracting A from B-that is, to finding R'' = B - A = -R). Show that this is the case.

Data given in Problem 5

Repeat the problem above, but reverse the order of the two legs of the walk; show that you get the same final result. That is, you first walk leg B, which is 20.0 m in a direction exactly 40° south of west, and then leg A, which is 12.0 m in a direction exactly 20° west of north. (This problem shows that A+B=B+ A.)

Data given in Problem 6

Suppose you first walk 12.0 m in a direction 20° west of north and then 20.0 m in a direction 40.0° south of west. How far are you from your starting point, and what is the compass direction of a line connecting your starting point to your final position? (If you represent the two legs of the walk as vector displacements A and B, as in Figure 3.51, then this problem finds their sum R = A + B.)

A + B = R B = 20 m 40 B . A R A 12 m YA FIGURE 3.51 W N to -20 X E