Calculate the depth below the surface of water at which the pressure due to the weight of

Question:

Calculate the depth below the surface of water at which the pressure due to the weight of the water equals 1.00 atm.

Strategy

We begin by solving the equation P=hρg for depth h:P h == pg

Then we take P to be 1.00 atm and ρto be the density of the water that creates the pressure.

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