Question: If a ({ }_{92}^{238} mathrm{U}) nucleus is struck by a neutron, it may absorb the neutron. The resulting nucleus then rapidly undergoes betaminus decay. The

If a \({ }_{92}^{238} \mathrm{U}\) nucleus is struck by a neutron, it may absorb the neutron. The resulting nucleus then rapidly undergoes betaminus decay. The daughter nucleus of that decay is A. \({ }_{91}^{239} \mathrm{~Pa}\)

B. \({ }_{92}^{239} \mathrm{U}\)

C. \({ }_{93}^{239} \mathrm{~Np}\)

D. \({ }_{94}^{239} \mathrm{Pu}\)

The uranium isotope \({ }^{235} \mathrm{U}\) can fission-break into two smaller-mass components and free neutrons-if it is struck by a free neutron. A typical reaction is \[{ }_{0}^{1} \mathrm{n}+{ }_{92}^{235} \mathrm{U} \rightarrow{ }_{56}^{141} \mathrm{Ba}+{ }_{36}^{92} \mathrm{Kr}+3{ }_{0}^{1} \mathrm{n}\]
As you can see, the subscripts (the number of protons) and the superscripts (the number of nucleons) "balance" before and after the fission event; there is no change in the number of protons or neutrons. Significant energy is released in this reaction. If a fission event happens in a large chunk of \({ }^{235} \mathrm{U}\), the neutrons released may induce the fission of other \({ }^{235} \mathrm{U}\) atoms, resulting in a chain reaction. This is how a nuclear reactor works.
The number of neutrons required to create a stable nucleus increases with atomic number. When the heavy \({ }^{235} \mathrm{U}\) nucleus fissions, the lighter reaction products are thus neutron rich and are likely unstable. Many of the short-lived radioactive nuclei used in medicine are produced in fission reactions in nuclear reactors.

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