A phase lead compensator has the transfer function [ mathrm{G}_{c}(s)=frac{10(1+0.04 s)}{(1+0.01 s)} ] The maximum phase angle
Question:
A phase lead compensator has the transfer function
\[
\mathrm{G}_{c}(s)=\frac{10(1+0.04 s)}{(1+0.01 s)}
\]
The maximum phase angle lead provided by this compensator will occur at a frequency \(\omega_{m}\) equal to
(a) \(50 \mathrm{rad} / \mathrm{sec}\)
(b) \(25 \mathrm{rad} / \mathrm{sec}\)
(c) \(10 \mathrm{rad} / \mathrm{sec}\)
(d) \(4 \mathrm{rad} / \mathrm{sec}\)
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