Question: The maximum phase shift that can be obtained by using a lead compensator with transfer function (mathrm{G}(s)=frac{4(1+0.15 s)}{(1+0.05 s)}) is equal to (a) (15^{circ}) (b)

The maximum phase shift that can be obtained by using a lead compensator with transfer function $\mathrm{G}(s)=\frac{4(1+0.15 s)}{(1+0.05 s)}$ is equal to
(a) $15^{\circ}$
(b) $30^{\circ}$
(c) $45^{\circ}$
(d) $60^{\circ}$.

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