Question: (Quadratic Forms) Let $Omega$ be a variance matrix and W a full-column rank matrix such that $WW' = Omega$. Let $W^+ = (W'W)^{-1}W'$ be the
(Quadratic Forms) Let $\Omega$ be a variance matrix and W a full-column rank matrix such that $WW' = \Omega$.
Let $W^+ = (W'W)^{-1}W'$ be the Moore-Penrose generalized inverse of W. Show
(a) $P_W = WW^+$ and $W^+y$ is the coefficient vector of W for the orthogonal projection of y onto Col(W),
(b) the quadratic form $y'\Omega^-y = (W^+y)'W'y$ is the squared length of the coefficient vector of W for the orthogonal projection of y onto Col(W),
(c) $W^+\Omega(W^+)' = I$, and
(d) $W'\Omega^-W = I$ for all generalized inverses $\Omega^-$.
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
