The flowrate in the clay-lined channel ((n=0.025)) shown in Fig. P10.54 is to be (300 mathrm{ft}^{3} /

Question:

The flowrate in the clay-lined channel \((n=0.025)\) shown in Fig. P10.54 is to be \(300 \mathrm{ft}^{3} / \mathrm{s}\). To prevent erosion of the sides, the velocity must not exceed \(5 \mathrm{ft} / \mathrm{s}\). For this maximum velocity, determine the width of the bottom, \(b\), and the slope, \(S_{0}\).

Figure P10.54

image text in transcribed

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Munson Young And Okiishi's Fundamentals Of Fluid Mechanics

ISBN: 9781119080701

8th Edition

Authors: Philip M. Gerhart, Andrew L. Gerhart, John I. Hochstein

Question Posted: