Question: The linear systems in Problems 110 are in echelon form. Solve each by back substitution. 2x 1 + x 2 + x 3 + x

The linear systems in Problems 1–10 are in echelon form. Solve each by back substitution.

2x1 + x2 + x3 + x4 = 6

         3x2 - X3 - 2x4 = 2

                 3x3 + 4x4 = 9

                             X4 = 6

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