Question: The linear systems in Problems 110 are in echelon form. Solve each by back substitution. x 1 - 2x 2 + 5x 3 - 3x

The linear systems in Problems 1–10 are in echelon form. Solve each by back substitution.

x1 - 2x2 + 5x3 - 3x4 = 7

        x2 - 3x3 + 2x4 = 3

                          X4 = -4

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