# Suppose the one-way valve of Fig. P1451 malfunctions due to corrosion and is stuck in its fully

## Question:

Suppose the one-way valve of Fig. P14–51 malfunctions due to corrosion and is stuck in its fully closed position (no air can get through). The fan is on, and all other conditions are identical to those of Prob. 14–51. Calculate the gage pressure (in pascals and in mm of water column) at a point just downstream of the fan. Repeat for a point just upstream of the one-way valve.

Data from Problem 14–51

A local ventilation system (a hood and duct system) is used to remove air and contaminants from a pharmaceutical lab (Fig. P14–51). The inner diameter (ID) of the duct is D = 150 mm, its average roughness is 0.15 mm, and its total length is L = 24.5 m. There are three elbows along the duct, each with a minor loss coefficient of 0.21. Literature from the hood manufacturer lists the hood entry loss coefficient as 3.3 based on duct velocity. When the damper is fully open, its loss coefficient is 1.8. The minor loss coefficient through the 90° tee is 0.36. Finally, a one-way valve is installed to prevent contaminants from a second hood from flowing “backward” into the room. The minor loss coefficient of the (open) one-way valve is 6.6. The performance data of the fan fit a parabolic curve of the form Havailable = H0 – aV̇2, where shutoff head H0 = 60.0 mm of water column, coefficient a = 2.50 × 10–7 mm of water column per (Lpm)2, available head Havailable is in units of mm of water column, and capacity V̇ is in units of Lpm of air. Estimate the volume flow rate in Lpm through this ventilation system.

FIGURE P14–51

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