Let us assume a quantum dot which is spherical The electrons or holes are confined at energy states with the following expression E nl (h 2 2m)( nl R) 2 , where m is the effective mass of the electron or hole and the value of nl is given by 10 , 11 4 49, 12 5 76, 20 6 28, 21 7 72, and 22 9 09 Now c...

The photon energy of the light emitted from the transition of an electron from the ...

Let us assume a quantum dot which is spherical. The electrons or holes are confined at energy

Question:

Let us assume a quantum dot which is spherical. The electrons or holes are confined at energy states with the following expression: E_nl = (h₂/2m∗)(α_nl/R)², where m* is the effective mass of the electron or hole and the value of α_nl is given by α₁₀⁼ π, α₁₁ = 4.49, α₁₂ = 5.76, α₂₀ = 6.28, α₂₁ = 7.72, and α₂₂ = 9.09. Now consider the very small GaAs quantum dots of radius 10 nm. If the electron drops from the second state (α₁₁) to the first state (α₁₀), what is the photon energy of the light emitted from this transition? Draw the energy diagram for GaAs quantum dots with radius 5 nm, 10 nm, and 15 nm. How does the first energy state change as a function of radius?