A 99.8 mL sample of a solution that is 12.0% KI by mass (d = 1.093 g/mL)
Question:
A 99.8 mL sample of a solution that is 12.0% KI by mass (d = 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb(NO3)2 by mass (d = 1.134 g/mL). How many grams of should form?
Pb(NO3)2(aq) + 2 KI(aq) → PbI2(s) + 2 KNO3(aq)
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1 Mass of KI solution 998 mL1093 gmL 1087 g Mass of PbNO32 solution 967 ...View the full answer
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Related Book For 
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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