Question: A laboratory method of preparing O 2 (g) involves the decomposition of KClO 3 (s). (a) How many moles of O 2 (g) can be

A laboratory method of preparing O2(g) involves the decomposition of KClO3(s).

2 KCIO3(s) 2 KCl(s) + 3 02(g)

(a) How many moles of O2(g) can be produced by the decomposition of 32.8 g KClO3?

(b) How many grams of KClO3 must decompose to produce 50.0 g O2?

(c) How many grams of KCl are formed, together with 28.3 g O2 in the decomposition of KClO3?

2 KCIO3(s) 2 KCl(s) + 3 02(g)

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a First calculate the number of moles of KClO3 in 328 g KClO3 nKClO3 328 g 1225 gmol 027 mol Then us... View full answer

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