(A) Suppose that the mercury level in Example 6-2 is 7.8 mm higher in the arm open to the atmosphere than in the closed arm. What would be the value of P_gas?

(B) Suppose P_bar. and P_gas are those described in Example 6-2, but the manometer is filled with liquid glycerol (d = 1.26 g/cm³) instead of mercury. What would be the difference in the two levels of the liquid?

Example 6-2

When the manometer in Figure 6-5(c) is filled with liquid mercury (d = 13.6 g/cm³) the barometric pressure is 748.2 mmHg, and the difference in mercury levels is 8.6 mmHg. What is the gas pressure P_gas?

Figure 6-5(c)

Transcribed Image Text:

Pha n bar. P gas P gas Gas = Pbar. + AP (AP=-gxhxd<0) (c) The gas pressure is less than the barometric pressure.