At 500 K, a 10.0 L equilibrium mixture contains 0.424 mol N₂, 1.272 mol H₂, and 1.152 mol NH₃. The mixture is quickly chilled to a temperature at which the NH₃ liquefies, and the NH₃(l) is completely removed. The 10.0 L gaseous mixture is then returned to 500 K, and equilibrium is re-established. How many moles of NH₃(g) will be present in the new equilibrium mixture?

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N2(g) + 3 H₂(g) = 2NH3 K 152 at 500 K =