Question: Given the equilibrium constant values 1 N2(g) + O2(g) = NO(g) K = 2.7 10-18 2 NO2(g) Kc = 4.6 x 10- Kc = 4.1

Given the equilibrium constant values

1 N2(g) + O2(g) = NO(g) K = 2.7 10-18 2 NO2(g) Kc = 4.6 x 10- Kc = 4.1 10- N2O4(g) N2(g) + O2(g) NO(g)

1 N2(g) + O2(g) = NO(g) K = 2.7 10-18 2 NO2(g) Kc = 4.6 x 10- Kc = 4.1 10- N2O4(g) N2(g) + O2(g) NO(g) N2(g) + O2(g) 2 Determine a value of K, for the reaction 2 NO(g) + 3 O(g) = 2 NO4(g)

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