In a solution that is 0.0500 M in [Cu(CN) 4 ] 3- and 0.80 M in free

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In a solution that is 0.0500 M in [Cu(CN)4]3- and 0.80 M in free CN-, the concentration of Cu+ is 6.1 x 10-32 M. Calculate Kf of [Cu(CN)4]3-.

Cut (aq) + 4CN (aq)  [Cu(CN)4](aq) K = ?

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Related Book For  answer-question

General Chemistry Principles And Modern Applications

ISBN: 9780132931281

11th Edition

Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette

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