Pentane is one of the most volatile of the hydrocarbons in gasoline. At 298.15 K, the following

Question:

Pentane is one of the most volatile of the hydrocarbons in gasoline. At 298.15 K, the following enthalpies of formation are given for pentane: ΔfH°[C5H12(l)] = -173.5 kJ mol-1; ΔfH°[C5H12(g)] = -146.9 kJ mol-1.

(a) Estimate the normal boiling point of pentane.

(b) Estimate ΔvapG° for pentane at 298 K.

(c) Comment on the significance of the sign of ΔvapG° for pentane at 298 K.

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  answer-question

General Chemistry Principles And Modern Applications

ISBN: 9780132931281

11th Edition

Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette

Question Posted: