What volume of 0.0665 M KMnO 4 is necessary to convert 12.5 g KI to I 2
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What volume of 0.0665 M KMnO4 is necessary to convert 12.5 g KI to I2 in the reaction below? Assume that H2SO4 is present in excess.
2 KMnO4 + 10 KI + 8 H2SO4 → 6 K2SO4 + 2 MnSO4 + 5 I2 + 8 H2O
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To determine the volume of 00665 M KMnO4 potassium permanganate required to convert 125 g of KI to I...View the full answer
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Related Book For
General Chemistry Principles And Modern Applications
ISBN: 9780132931281
11th Edition
Authors: Ralph Petrucci, Jeffry Madura, F. Herring, Carey Bissonnette
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