A flask contains 49.8 mL of 0.150 M Ca(OH) 2 (calcium hydroxide). How many milliliters of 0.500
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A flask contains 49.8 mL of 0.150 M Ca(OH)2 (calcium hydroxide). How many milliliters of 0.500 M Na2CO3 (sodium carbonate) are required to react completely with the calcium hydroxide in the following reaction?
Na2CO3(aq) + Ca(OH)2(aq) → CaCO3(s) + 2NaOH(aq)
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