Question: A flat belt is required to transmit (35 mathrm{~kW}) from a pulley of (1.5 mathrm{~m}) effective diameter running at 300 (mathrm{rpm}). The angle of contact

A flat belt is required to transmit \(35 \mathrm{~kW}\) from a pulley of \(1.5 \mathrm{~m}\) effective diameter running at 300 \(\mathrm{rpm}\). The angle of contact is spread over 11/24 of the circumference and the coefficient of friction between belt and pulley is 0.3 . The belt thickness is \(9.5 \mathrm{~mm}\) and its density is \(1100 \mathrm{~kg} / \mathrm{m}^{3}\). If the permissible stress in the belt is \(2.5 \mathrm{~N} / \mathrm{mm}^{2}\), determine the width of belt required.

Step by Step Solution

3.39 Rating (143 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

Determining the Width of the Belt for Power Transmission Heres how to find the width of the flat bel... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Introduction Mechanical Engineering Questions!