Question: A flat belt is required to transmit (35 mathrm{~kW}) from a pulley of (1.5 mathrm{~m}) effective diameter running at 300 (mathrm{rpm}). The angle of contact
A flat belt is required to transmit \(35 \mathrm{~kW}\) from a pulley of \(1.5 \mathrm{~m}\) effective diameter running at 300 \(\mathrm{rpm}\). The angle of contact is spread over 11/24 of the circumference and the coefficient of friction between belt and pulley is 0.3 . The belt thickness is \(9.5 \mathrm{~mm}\) and its density is \(1100 \mathrm{~kg} / \mathrm{m}^{3}\). If the permissible stress in the belt is \(2.5 \mathrm{~N} / \mathrm{mm}^{2}\), determine the width of belt required.
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