Given below are values of G E /Jmol 1 , H E /Jmol 1 , and C
Question:
Given below are values of GE /J·mol−1, HE /J·mol−1, and CEP / J · mol −1· K−1 for some equimolar binary liquid mixtures at 298.15 K. Estimate values of GE, HE, and SE at 328.15 K for one of the equimolar mixtures by two procedures: (I) Use all the data; (II) Assume CEP = 0. Compare and discuss your results for the two procedures.
(a) Acetone/chloroform: GE = − 622, HE = − 1920, CEP = 4.2.
(b) Acetone/n-hexane: GE = 1095, HE = 1595, CEP = 3.3.
(c) Benzene/isooctane: GE = 407, HE = 984, CEP = − 2.7.
(d) Chloroform/ethanol: GE = 632, HE = − 208, CEP = 23.0.
(e) Ethanol/n-heptane: GE = 1445, HE = 605, CEP = 11.0.
(f) Ethanol/water: GE = 734, HE = − 416, CEP = 11.0.
(g) Ethyl acetate/n-heptane: GE = 759, HE = 1465, CEP = − 8.0.
Step by Step Answer:
Introduction To Chemical Engineering Thermodynamics
ISBN: 9781259696527
8th Edition
Authors: J.M. Smith, Hendrick Van Ness, Michael Abbott, Mark Swihart