The heat of vaporization of ether is (25.98 mathrm{~kJ} / mathrm{mol}) at its boiling point, (34.5^{circ} mathrm{C}).

Question:

The heat of vaporization of ether is \(25.98 \mathrm{~kJ} / \mathrm{mol}\) at its boiling point, \(34.5^{\circ} \mathrm{C}\).

(a) Calculate the rate of change of vapour pressure with temperature \(\frac{d P}{d T}\) at the boiling point.

(b) What is the boiling point at \(750 \mathrm{~mm}\) ?

(c) Estimate the vapour pressure at \(36^{\circ} \mathrm{C}\).

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: