The system ethanol(1) + bromoethane(2) forms an azeotrope containing 93.2 mol% bromoethane and having a minimum boiling
Question:
The system ethanol(1) + bromoethane(2) forms an azeotrope containing 93.2 mol% bromoethane and having a minimum boiling point of 37.0°C at 760 mmHg. The following vapor pressure data are available:
(a) Use all of the available data to determine coefficients for equation log10Psat = A + B/T by performing a linear regression to find the coefficients A and B. Be sure to use temperature in Kelvin.
(b) Use the azeotropic point to determine the parameters for the van Laar equation.
(c) Generate a P-x-y diagram at 100C. Tabulate the data used to plot the diagram.
(d) Generate a T-x-y diagram at 760 mmHg. Assume that the activity coefficients are independent of temperature over the range of temperature involved. (This is the type of calculation necessary for generating an x-y diagram for a distillation at 760 mmHg.)
(e) Experimentally, the system is found to have a homogeneous maximum pressure azeotrope (Smyth, C.P., Engel, E.W. 1929. J. Am. Chem. Soc., 51:2660). How does this compare with your findings?
Step by Step Answer:
Introductory Chemical Engineering Thermodynamics
ISBN: 9780136068549
2nd Edition
Authors: J. Elliott, Carl Lira