Question: Although the Schrdinger equation for helium itself cannot be solved exactly, there exist helium-like systems that do admit exact solutions. A simple example is rubber-band

Although the Schrödinger equation for helium itself cannot be solved exactly, there exist “helium-like” systems that do admit exact solutions. A simple example is “rubber-band helium,” in which the Coulomb forces are replaced by Hooke’s law forces:

H = - 2 - - (V + V) + {ma (r

(a) Show that the change of variables from r1,r2, to

+r) ^\_m6|r - 1/ 2m (8.78)

turns the Hamiltonian into two independent three-dimensional harmonic oscillators:

(b) What is the exact ground state energy for this system?
(c) If we didn’t know the exact solution, we might be inclined to apply the method of Section 8.2 to the Hamiltonian in its original form (Equation 8.78). Do so (but don’t bother with shielding). How does your result compare with the exact answer?

H = - 2 - - (V + V) + {ma (r +r) ^\_m6|r - 1/ 2m (8.78)

Step by Step Solution

3.33 Rating (168 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

a b c The ground state for a onedimensional oscillator is The r 1 r 2 term int... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Introduction To Quantum Mechanics Questions!