Two adjacent BSs i and j are 30 km apart. The signal strength received by the MS

Question:

Two adjacent BSs i and j are 30 km apart. The signal strength received by the MS is given by the following expressions.

GG.P L(x) P(x) =


Where

L(x) =69.55+26.16log,f. (MHz)–13.82log,A (m) - a[h(m)] +[44.9-6.55log,h (m)]log(x).


and x is the distance of the MS from BS i. Assume unity gain for Gr and Gt, given that Pi(t) = 10 Watts, = 100 Watts, fc = 300 MHz, hb = 40 m, hm = 4 m, α = 3.5, x = 1 km, and Pj(t) is the transmission power of BS j.

(a) What is the power transmitted by BS j, so that the MS receives signals of equal strength at x?

(b) If the threshold value E = 1 dB and the distance where handoff is likely to occur is 2 km from BS j, then what is the power transmitted by BS j?

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  book-img-for-question

Introduction to Wireless and Mobile Systems

ISBN: ?978-1305087132

4th edition

Authors: Dharma P. Agrawal, Qing An Zeng

Question Posted: