Lead(II) sulfide reacts with hydrogen peroxide to give lead(II) sulfate as shown in the unbalanced chemical equation PbS H 2 O 2 PbSO 4 H 2 O If 63 2 g of PbS is reacted with 48 0 g of H 2 O 2 , (a) Which is the limiting reagent (b) How many grams of excess reactant remain after the reaction is com...

a To determine the limiting reagent we need to compare the number of moles of each reactant and see ...

Lead(II) sulfide reacts with hydrogen peroxide to give lead(II) sulfate as shown in the unbalanced chemical equation

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Lead(II) sulfide reacts with hydrogen peroxide to give lead(II) sulfate as shown in the unbalanced chemical equation

PbS + H₂O₂ → PbSO₄ + H₂O

If 63.2 g of PbS is reacted with 48.0 g of H₂O₂,

(a) Which is the limiting reagent?

(b) How many grams of excess reactant remain after the reaction is complete?

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Introductory Chemistry Atoms First

ISBN: 9780321927118

5th Edition

Authors: Steve Russo And Michael Silver

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Question Posted: Dec 04, 2023 08:17 AM

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Lead(II) sulfide reacts with hydrogen peroxide to give lead(II) sulfate as shown in the unbalanced chemical equation

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a To determine the limiting reagent we need to compare the number of moles of each reactant and see ...View the full answer

Introductory Chemistry Atoms First

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