The reaction is run in a 10.0-L vessel. The vessel is loaded with 1 mole of CO

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The reaction

CO(g) + 3H(g)  CH4(g) + HO(g)

is run in a 10.0-L vessel. The vessel is loaded with 1 mole of CO and 3 moles of H2. At equilibrium, the amounts are 0.613 mole of CO, 1.839 moles of H2, 0.387 mole of CH4, and 0.387 mole of H2O. What is the value of the equilibrium constant for this reaction? Describe the position of the equilibrium.

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Related Book For  answer-question

Introductory Chemistry Atoms First

ISBN: 9780321927118

5th Edition

Authors: Steve Russo And Michael Silver

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