Given that 27.5 mL of 0.210 M lithium iodide solution reacts with 0.133 M lead(II) nitrate solution,

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Given that 27.5 mL of 0.210 M lithium iodide solution reacts with 0.133 M lead(II) nitrate solution, what volume of Pb(NO3)2 solution is required for complete precipitation? 

Pb(NO3)2(aq) + 2 LiI(aq) → PbI2(s) + 2 LiNO3(aq)

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