Find the projection of v onto u. Figure 1.39 suggests two ways in which vectors may be

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Find the projection of v onto u.

3.01 1.34 4.25 -0.33 ,v = -1.66 2.52

Figure 1.39 suggests two ways in which vectors may be used to compute the area of a triangle. The area A of
- proju(v) (a) (b)

the triangle in part (a) is given by 1 / 2 ˆ¥uˆ¥ˆ¥v - proju(v)ˆ¥, and part (b) suggests the trigonometric from of the area of a triangle: A = 1 / 2ˆ¥uˆ¥ˆ¥vˆ¥sinθ (We can use the identity sinθ = ˆš1 - cos2θ to find sin θ.)

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