Suppose we encode the four vectors in by repeating the vector twice. Thus, we have [0,0] [0,0,0,0]
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Suppose we encode the four vectors in by repeating the vector twice. Thus, we have
[0,0]→ [0,0,0,0]
[0,1]→ [0,1,0,1]
[1,0]→ [1,0,1,0]
[1,1]→ [1,1,1,1]
Show that this code is not error-correcting.
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We have the following set of vectors in Z 2 2 and their encoded vectors as 0 0 0 0 0 0 0 1 0 1 0 ...View the full answer
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