We would like to price the floor on the composition defined in Problem 8.22 using the LIBOR

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We would like to price the floor on the composition defined in Problem 8.22 using the LIBOR Market model. Now, we assume that the LIBOR Li(t) follows the arithmetic Brownian process:

Titl dL;(t) = o(t) dz!+ (t) i=1,2,..., n  1.

Problem 8.22

Consider a floor on composition, where the composition is defined as 

n-1 ][(1+&+1Li). i=1

Here, Li is reset at time Ti and αi+1 is the accrual factor over the time interval (Ti,Ti+1]. The payment of this floor at maturity Tn is

max (n-1 + (1 + ai+1 Li), K \i=1

Assuming that the discounted bond price process follows the same process as in Problem 8.21, show that the time-0 value of this floor on composition is given by (Henrard, 2005)

F(0; , where and ... ) = B(0, T1)N (k + x) + K B(0, Th)N(-k), n-1n-1 emin(T;,T;) '= i=1 j=1 k = 1 din  [B(u,Problem 8.21

Assume that the T-maturity discounted bond price process B(t,T) follows the one-factor Gaussian HJM under the risk neutral measure Q:

dB(t, T) B(t, T) =r dt - OB(t, T) dZ.A caption is a call option on a cap, whose terminal payoff at time T is given by

max  c;(T; Ti-1, T;)  X, 0 i=1 T < T < T

Here, Ci(T ; Ti−1,Ti) is the time-T value of a caplet with payment on the LIBOR Li−1 at time Ti and X is the strike price, i = 1, 2, ··· ,n. Since a cap can be visualized as a series of put options on the zero-coupon bonds, a caption is seen as a compound call on a put. By applying Jamshidian’s decomposition technique (Jamshidian, 1989) for an option on a coupon-bearing bond, find the time-t value of the caption, t

Use the identity 

n-1 B(u, Th)  B(u, T;) = B(u, Tj+1)  B(u,T;)] j=1 to show that =  i=1 Ti [B(u, Ti+1)  B(u, T;)] [2B(u, T)

Here, σLi (t) is the deterministic volatility function and ZTi+1i (t) is QTi+1- Brownian. By making the “frozen coefficient” assumption in the drift term of the stochastic differential equation of Li(t) under the terminal measure QTn , show that the time-0 value of the floor on composition is given by (Henrard, 2005)

F(0; T,, Tn) = B(0, T)N(k+o) + KB(0, Tn)N(-k), 0 T, whereo = AT SA and k = -=- [I In B(0, T) KB(0, Tn) T 1 1 2 - (200.79) ++ 200, 7) ++) = 1 L(0, T) L(0, " 2

αi+1 is the accrual factor of (Ti,Ti−1), i = 1, 2, ··· ,n − 1, and the (i, j)th entry of the matrix S is given by

(S)ij = min(Ti,Tj) S o(u)o(u) du, i, j = 1,2,..., n - 1.

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