Show that the shape (r(varphi)) for a central spring force ellipse takes the standard form (r^{2}=a^{2} b^{2}

Question:

Show that the shape \(r(\varphi)\) for a central spring force ellipse takes the standard form \(r^{2}=a^{2} b^{2} /\left(b^{2} \cos ^{2} \varphi+a^{2} \sin ^{2} \varphi\right)\) if (in equation 7.37) we use the plus sign in the denominator and choose \(\varphi_{0}=\pi / 4\).

Data from equation 7.37

image text in transcribed

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Related Book For  answer-question

Modern Classical Mechanics

ISBN: 9781108834971

1st Edition

Authors: T. M. Helliwell, V. V. Sahakian

Question Posted: