Question: For the He wave function, use with Z eff = 2 - 5/16, as obtained by the variational method. The measured value of the diamagnetic

For the He wave function, use(X1, X2) = (Zeff/a)exp - Zerr(r+r2) ao

with Zeff = 2 - 5/16, as obtained by the variational method. The measured value of the diamagnetic susceptibility is 1.88 x 10-6 cm3/mole.

Using the Hamiltonian for an atomic electron in a magnetic field, determine, for a state of zero angular momentum, the energy, change to order B2 if the system is in a uniform magnetic field represented by the vector potential A = 1/2B x r.

Defining the atomic diamagnetic susceptibility x by E = -1/2X B2, calculate x for a helium atom in the ground state and compare the result with the measured value.

(X1, X2) = (Zeff/a)exp - Zerr(r+r2) ao

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The trial wave function given in problem 519 for the helium atom is x1 x2 Zeff na expZeffr1 r2 16 where Zeff is the effective nuclear charge a is the ... View full answer

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