An alkane (A) with the formula C₆H₁₄ reacts with chlorine to yield three compounds with the formula C₆H₁₃Cl: B, C, and D. Of these only C and D undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover, C and D yield the same alkene E (C6H12). Hydrogenation of E produces A. Treating E with HCl produces a compound (F) that is an isomer of B, C, and D. Treating F with magnesium in dry ether followed by aqueous acid gives a compound (G) that is isomeric with A. Propose structures for A–G.