Let pH - pK a = . Starting with Eqs. 3.30c and 3.30d, derive Eqs. 3.31a and

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Let pH - pK_a = Δ. Starting with Eqs. 3.30c and 3.30d, derive Eqs. 3.31a and 3.31b. fA= = 10-PK 10 PK + 10-PH (3.30c)

JAH = [AH] [A] + [AH] [AH] (K[AH]/[H3O+]) + [AH] = [H3O+] K + [H3O+] a 10-PH 10-PK + 10-PH (3.30d) JA JAH = 1 1 + 10-A 1 1 + 10A (3.31a) (3.31b)

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Organic Chemistry

ISBN: 9781936221349

6th Edition

Authors: Marc Loudon, Jim Parise

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Question Posted: Dec 02, 2023 03:47 AM

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Let pH - pK a = . Starting with Eqs. 3.30c and 3.30d, derive Eqs. 3.31a and

Question:

fA= = 10-PK₁ 10 PK + 10-PH (3.30c)

Step by Step Answer:

Derivation of Eq 331a from Eq 330c 10P 10 P 10...View the full answer

Organic Chemistry

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